complements

์ด๋ฒคํŠธ A์˜ ์—ฌ์ง‘ํ•ฉ(Complements) ์€ A'์œผ๋กœ ํ‘œ๊ธฐํ•˜๋ฉฐ, A๊ฐ€ ๋ฐœ์ƒํ•˜์ง€ ์•Š์„ ๋ชจ๋“  ํ™•๋ฅ ์„ ์ผ์ปซ๋Š”๋‹ค. (A^c๋กœ ํ‘œ๊ธฐํ•˜๊ธฐ๋„ ํ•ฉ๋‹ˆ๋‹ค.)์ฆ‰, P(A) + P(A') = 1 ์ด๊ณ , ์ด ๋ง์€ P(A') = 1 - P(A) ์ด๋‹ค.๋˜ํ•œ P((A')') = P(A)์ด๋‹ค. (์—ฌ์ง‘ํ•ฉ์˜ ์—ฌ์ง‘ํ•ฉ์€ ์›๋ณธ ์ง‘ํ•ฉ) ์—ฌ์ง‘ํ•ฉ์˜ ์ ์ ˆํ•œ ํ™œ์šฉ์€ ๊ณ„์‚ฐ์„ ๋” ์šฉ์ดํ•˜๊ฒŒ ํ•œ๋‹ค.P(A) = ์ฃผ์‚ฌ์œ„์—์„œ 1, 2, 3, 4, 6์ด ๋‚˜์˜ฌ ํ™•๋ฅ ์ด๋ผ๊ณ  ํ•ด๋ณด์ž.P(A) = 1- P(A')์ด๊ณ , ์ด ๋ง์˜ ๋œป์€ P(A) = 1 - (5๊ฐ€ ๋‚˜์˜ฌ ํ™•๋ฅ ) ์ด๋‹ค.5๊ฐ€ ๋‚˜์˜ฌ ํ™•๋ฅ ์€ 1/6์ด๊ธฐ ๋•Œ๋ฌธ์—, P(A) = 1 - 1/6 = 5/6์ด๋‹ค.  1~6๊นŒ์ง€ 5๋ฅผ ์ œ์™ธํ•˜๊ณ  ๊ฐ ์ˆซ์ž๊ฐ€ ๋‚˜์˜ฌ ํ™•๋ฅ ์„ ๊ตฌํ•ด ๋”ํ•˜๋Š”๊ฒƒ๋ณด๋‹ค 5๊ฐ€ ๋‚˜์˜ฌ ํ™•๋ฅ ์„ ๊ตฌํ•ด์„œ 1์—์„œ ๋นผ๋Š”๊ฒŒ ๋”์šฑ ํŽธ๋ฆฌํ•˜๋‹ค.
Chan Lee
'complements' ํƒœ๊ทธ์˜ ๊ธ€ ๋ชฉ๋ก